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Find the limits.$$\lim _{x \rightarrow+\infty} x^{1 / x}$$
$$\lim _{x \rightarrow+\infty} x^{\frac{1}{x}}=1$$
Calculus 1 / AB
Chapter 3
TOPICS IN DIFFERENTIATION
Section 6
L Hopital's Rule; Indeterminate Forms
Functions
Limits
Derivatives
Differentiation
Continuous Functions
Applications of the Derivative
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So we're looking at the limit as X goes to infinity of X to the one over X. Let's start by assigning this limit l So let's take the natural log of each side and we can swap the natural log with the limit by the function limit interchange property because natural log is a continuous function. Okay, And now let's go ahead and use one of our log properties that says that we can take the exponents and bring it in front. So this simplifies to natural log of acts over X. And if we tried Teoh, take the limit of this thing. Noticed that we get infinity over infinity. So we're good to go to use low petals rule. So if we apply low petals rule in the numerator, we get one over X and then the denominator we get one. We can evaluate this zero so we have that the natural log of L is equal to zero. That implies that l is equal to one and that's it
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