our path is defined. That's too cube T to the fourth 40 from what have to one. So the modern conservative will be swear with three t squared waas 40 Cute square two squared. So yes, sir will be this word. Friends? Sure. With nine plus 16 square sit 70 square over half See Is the insulin is scoring? Why over as X over the past C. D s plugging the trajectory function are for Passy. We have I wouldn't have to. One square with t to the fourth over. T cute times t squared times sort of 16. Thinks were close 90 t and the answer before this is where we'll be when 25 mourners 13 swear with 13 over 48.

## Discussion

## Video Transcript

our path is defined. That's too cube T to the fourth 40 from what have to one. So the modern conservative will be swear with three t squared waas 40 Cute square two squared. So yes, sir will be this word. Friends? Sure. With nine plus 16 square sit 70 square over half See Is the insulin is scoring? Why over as X over the past C. D s plugging the trajectory function are for Passy. We have I wouldn't have to. One square with t to the fourth over. T cute times t squared times sort of 16. Thinks were close 90 t and the answer before this is where we'll be when 25 mourners 13 swear with 13 over 48.

## Recommended Questions

Find the line integral of $f ( x , y ) = \sqrt { y } / x$ along the curve $\mathbf { r } ( t ) = t ^ { 3 } \mathbf { i } + t ^ { 4 } \mathbf { j } , 1 / 2 \leq t \leq 1$

Find the line integral of $f ( x , y ) = y e ^ { x ^ { 2 } }$ along the curve $\mathbf { r } ( t ) = 4 t \mathbf { i } - 3 t \mathbf { j } , - 1 \leq t \leq 2$

Find the line integral of $f(x, y)=y e^{x^{2}}$ along the curve $\mathbf{r}(t)=4 t \mathbf{i}-3 t \mathbf{j},-1 \leq t \leq 2$.

Find the line integral of $f ( x , y , z ) = \sqrt { 3 } / \left( x ^ { 2 } + y ^ { 2 } + z ^ { 2 } \right)$ over the curve $\mathbf { r } ( t ) = t \mathbf { i } + t \mathbf { j } + t \mathbf { k } , 1 \leq t \leq \infty$

Find the line integral of $f(x, y, z)=\sqrt{3} /\left(x^{2}+y^{2}+z^{2}\right)$ over the curve $\mathbf{r}(t)=t \mathbf{i}+t \mathbf{j}+t \mathbf{k}, 1 \leq t \leq \infty$.

Find the line integral of $f ( x , y ) = x - y + 3$ along the curve $\mathbf { r } ( t ) = ( \cos t ) \mathbf { i } + ( \sin t ) \mathbf { j } , 0 \leq t \leq 2 \pi$

Find the line integral of $f(x, y)=x-y+3$ along the curve $\mathbf{r}(t)=(\cos t) \mathbf{i}+(\sin t) \mathbf{j}, 0 \leq t \leq 2 \pi$.

Evaluate the line integral, where $ C $ is the given curve.

$ \displaystyle \int_C y \, dx + z \, dy + x \, dz $,

$ C: x = \sqrt{t} $, $ y = t $, $ z = t^2 $, $ 1 \leqslant t \leqslant 4 $

Evaluate the line integral, where $ C $ is the given curve.

$ \displaystyle \int_C xye^{yz} \, dy $,

$ C: x = t $, $ y = t^2 $, $ z = t^3 $, $ 0 \leqslant t \leqslant 1 $

Evaluate the line integral, where $ C $ is the given curve.

$ \displaystyle \int_C (x/y) \, ds $, $ C: x = t^3 $, $ y = t^4 $, $ 1 \leqslant t \leqslant 2 $