00:01
Okay, so for this problem, we're going to need to find f of x zero.
00:10
So that means we're going to plug one into this function, so that'll give us 2 over 1, which is just equal to 2.
00:16
Then from here we need to also find the derivative, so f prime of x.
00:22
So derivative of 2 over x is negative 2 over x squared.
00:29
Then from here we want to plug 1 into the derivative.
00:33
So this will give us negative 2 over 1 squared.
00:43
So this will just be negative 2.
00:45
So now we can plug what we know into our l of x formula.
00:50
So l of x is approximately equal to f of x, which is equal to, so f prime of x zero, which you found here to be negative 2, and then times x minus x of 0, which is 1...