For the function $f(x, y, z)=x^{2}+y^{2}+z^{2}$, we substitute the given points into the function.
For point (1,1,1), $f(1,1,1)=1^{2}+1^{2}+1^{2}=3$.
For point (0,1,0), $f(0,1,0)=0^{2}+1^{2}+0^{2}=1$.
For point (1,0,0), $f(1,0,0)=1^{2}+0^{2}+0^{2}=1$.
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