00:01
High in the given problem the four current carrying conductors are perpendicular to the plane of paper and arranged such as to be passing through the four corners of a square as we have done in the earlier problem problem number 84 also these four current carrying conductors are, first of all this, suppose the corner is a, another at b, both of these conductors are carrying current which is coming out of the plane of paper.
00:43
Then here this is c carrying current into the plane of paper and here this is d, which is also carrying current into the plane of paper.
00:52
Now we have to find magnetic field here at this point are.
00:57
The side length of this square is given as d where the value of this d is 0 .10 meter and current passing through each conductor is having the same magnitude 10 .0 ampere.
01:11
If we join this observation point r with these two corners of the square using pythagoros theorem, these lengths will come out to be same.
01:24
Means b r is equal to d r and that is d root 5 by 2 as we have done earlier in the previous problem problem number 84 we have obtained these distances and then we have obtained the magnetic fields also due to these current carrying conductors put at b and d and using right hand thumb rule the directions of magnetic fields at this observation point are as shown in the figure...