Question
Find the magnitude and direction angle (to the nearest tenth) for each vector. Give the measure of the direction angle as an angle in $\left[0,360^{\circ}\right)$.$$\langle 0,-12\rangle$$
Step 1
In this case, the vector is $\langle 0,-12 \rangle$, so the magnitude is $\sqrt{0^2 + (-12)^2} = \sqrt{144} = 12$. Show more…
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