Question
Find the magnitude and direction of $($ a) $9 \bar{B}-3 \vec{A}$ and $(b)-5 \vec{A}+8 \vec{B}$, where $\vec{A}=(23.0,59.0), \vec{B}=(90.0,-150.0)$
Step 1
We can do this by multiplying the components of $\vec{A}$ and $\vec{B}$ by the corresponding scalars and then subtracting or adding them. For $9\vec{B}-3\vec{A}$, the x-component is $9B_x - 3A_x = 9(90.0) - 3(23.0) = 810 - 69 = 741$ and the y-component is $9B_y - Show more…
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