00:01
So the total mass of the solution is equal to 50 grams, and the mole fraction of urea in the solution is 0 .077.
00:20
The molar mass of the solute is equal to 60 grams per mole, and the molar mass for water is 18 grams per mole.
00:39
So let's consider the mass of the urea as m.
00:44
So m as the mass of the solid.
00:48
So the mass of water is equal to 50 minus m.
01:00
So we consider the following relationship, mole fraction of a solute is equal to number of moles of the solute divided by most of solute plus of solvent.
01:21
And most of solute can be calculated by mass divided by molar mass.
01:29
So most of the solute urea is equal to m divided by 60.
01:43
And the moles of water is equal to 50 minus m divided by 18.
01:57
So now we calculate the more fraction of urea with the new equation.
02:07
More fraction of urea equal to 0 .770, that is, n of the solute divided by n of solute, plus, in a solvent so we want to plug in these two numbers form we have 0 .77 equal to x divided by 60 divided by x divided by 60 plus 50 minus x divided by 18 so if we combine these two terms together we get 3x plus 10 times 50 minus x divided by 118...