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Find the mean deviation about median for the following data :$$\begin{array}{|c|c|c|c|c|c|c|}\hline \text { Marks } & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 & 50-60 \\\hline \begin{array}{c}\text { Number of } \\\text { Girls }\end{array} & 6 & 8 & 14 & 16 & 4 & 2 \\\hline\end{array}$$
Intro Stats / AP Statistics
Chapter 15
Statistics
Section 1
Introduction
Descriptive Statistics
Temple University
Missouri State University
Boston College
Lectures
0:00
01:54
Find the mean and the stan…
01:21
Find the mean, median, and…
00:50
03:27
00:36
01:09
04:47
The given values represent…
06:42
Find the variance and stan…
03:07
01:24
hell in this problem, we have to find the main division about median by using the given data. So here, in this table, we have given the month number of girls, that is F. I. And the mid value of this class interval, that is X. I. Now, in order to find the main deviation about median. First of all, we will find the median for that we have to find humiliated frequency. So here we have 6, 6 plus eight is 14, 14 plus 14 is 28, 28 plus 16 is 44, 44 plus four is 48 48 plus two is 15 And the submission of f. i. S. So here we have and upon two is equal to 15.2, which is equal to 25. Therefore, the maiden class is 20 to 30 so we have million is equals two, 20 plus 25 -14. upon 14 in 2 10, by simplifying it, we get median is equals two 20 plus 7.86 which is equals two, 27.86. Now, in order to find the main deviation about median, we will find the absolute deviation from the median Since we are finding the absolute deviation, so we will ignore the negative sign. So here we have 5 -27.86 is 22.8 sets, 15 -27.86 is 12.86, 25 -27.86 is 2.86, 35 -30, is 7.14, 45 -27.86 is 17.14 and 55 -27.86 is 27.14. Similarly, we will find a fi into absolute value of deviation from meeting it would be six into 27.86 is 137.16, 8 into 12.86 is 102.88, 14 into 2.86 is 40.04, 16 into 7.14 is 114.2 full four in 2, is 68.56, two into 27.14 is 54.28 And the submission is 517.16. Now, we will find main division about meeting that is run upon and into sigma. If I into exile -27.86, well, I goes from 1 to N by substituting the known values, we get mean deviation is equal to one upon, 50 into 517.16, Which is equal to 10.34. Hence, we get me in division about meeting As equals to 10.34
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