Find the mean deviation about the mean for the data.
$$
\begin{array}{|c|c|c|c|c|c|c|}
\hline \begin{array}{c}
\text { Height } \\
\text { in cms }
\end{array} & 95-105 & 105-115 & 115-125 & 125-135 & 135-145 & 145-155 \\
\hline \begin{array}{c}
\text { Number of } \\
\text { boys }
\end{array} & 9 & 13 & 26 & 30 & 12 & 10 \\
\hline
\end{array}
$$

Answer

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Intro Stats / AP Statistics

NCERT Class 11 - Math

Chapter 15

Statistics

Section 1

Introduction

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Problem 1

Problem 2

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Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Video Transcript

here in this problem, we have to find the main deviation about me by using the given data. So in this table we have given height in centimeter number of boys, that is a five and and I have found the mid value that is exciting. Now, in order to find the mean deviation about me, first of all, we will find if I excite, So here we have 102, 9 is 900, 110 into 13 is 1430. 120 into 26 is 30. in 230 is 3900, 114 to 12 is 1680 And 115 to 10 years, 1500. Now we will find the mean, that is Mean as equals two, one upon N sigma. If I exciting. Well, I goes from one to n by substituting the known values, we get Men, which is equals two, one upon 100 into 12,530 It would be equals two, 125.3. Now we will find the absolute value of deviation from the main. So here we have XI -125.3 since we are finding the absolute value, so we will ignore the negative sign. So here we have 100 -125.3 is 25.5 100 -125.3 years, 25.3, 110 -125.3 is 15.3, 120 -125.3 is 5.3, 130 -125.3 is 4.7, 140 -125.3 is 14.7, 150 -125.3 is 24.7. Now, we will find a fly into absolute value of deviation from the mean, it would be 925.3, which is 227.7 pertaining to 15.3 is 198.9 26 in two, is 137.8, 13 to 4.7 is 141, 12 into 14.7 is 176.4, 10 into 24.7 is 247 and this emission is 1128.8. Now the main deviation about mean is equals two Van upon n sigma phi In two XI -125.3. Well, I goes from one to and by substituting the known values we get mean deviation about mean is equal to one upon 100 into 1,128.8, Which is equals to 11.28. Hence, we get me innovation about me As equals to 11.28.

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