Find the mean deviation about the median for the data.
$$
36,72,46,42,60,45,53,46,51,49
$$

Answer

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Intro Stats / AP Statistics

NCERT Class 11 - Math

Chapter 15

Statistics

Section 1

Introduction

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Problem 1

Problem 2

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Problem 5

Problem 6

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Problem 9

Problem 10

Problem 11

Problem 12

Video Transcript

here in this problem, we have to find the mean deviation about the median. But given data, first of all, we will find the mean in order to find the mean, we will arrange their data in ascending order. We have it is X coma what they do, coma 45 comma 46, comma 46, comma 49, comma 51, coma 53, comma 60, 72. Here we have N is equal to 10, which is even So median is the average of 5th and 6th observation, so we get the meeting is equals two 46 plus 49 upon to It would be equals two 27.5. Now we will find the respective absolute values of deviation from the median that is x y minus meeting since we are finding the absolute derivatives, so we will ignore the negative sign. So it would be 36 -47.5. Here we have median, which is 47.5, So we get 36 -47.5 would be 11.5 Bless 40 to -47.5 would be 5.5 plus 45 -47.5 years, 2.5 plus 46 -47.5 is 1.5 plus 46 -47.5 is 1.5, Yes plus 46 -47.5 is 1.5 Bless 49 -47.5 is 3.5 Plus 49 -47.5 is 1.5 plus 51 -47.5 is 3.5 Plus 53 -47.5 is 5.5 Plus 60 -47.5 is 12.5 plus 70 -47.5 is 24.5, It would be equal to 70. Now, we will find the main division about meeting. We know that main division about median is equal to run upon and into submission of x i minus meeting right I goes from 1 to N. So by substituting the values we get. Main deviation about meeting is equal to One upon 10 into 70, it would be equal to seven. Therefore, we get Main Division about median is equal to seven.

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