Question
Find the minimum and maximum values of the function on the given interval by comparing values at the critical points and endpoints.$y=x^{3}-24 \ln x, \quad\left[\frac{1}{2}, 3\right]$
Step 1
The derivative of $x^{3}$ is $3x^{2}$ and the derivative of $-24 \ln x$ is $-24/x$. So, the derivative of the function is $y'=3x^{2}-24/x$. Show more…
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