Question
Find the missing factor in the numerator such that the two fractions are equivalent.$$\frac{x+3}{2(x-1)}=\frac{(x+3)(\quad)}{2(x-1)^{2}}$$
Step 1
The denominators of the two fractions give us a clue. The denominator of the first fraction is $2(x-1)$ and the denominator of the second fraction is $2(x-1)^{2}$. Show more…
Show all steps
Your feedback will help us improve your experience
Matthew Biollo and 93 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the missing factor in the numerator such that the two fractions are equivalent. $$\frac{2}{3 x^{2}}=\frac{2(\quad)}{3 x^{4}}$$
Prerequisites
Rational Expressions
Find the missing factor in the numerator such that the two fractions are equivalent. $$\frac{x-1}{4(x+2)}=\frac{(x-1)(\quad)}{4(x+2)^{2}}$$
Multiply the numerator and the denominator of each fraction by the given factor and obtain an equivalent fraction. $$\frac{2}{x+3} \quad(\text { by } x-2)$$
Factoring and Fractions
Equivalent Fractions
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD