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Find the molarity of a 40.0$\%$ by mass aqueous solution of sulfuric acid, for which the density is 1.3057 $\mathrm{g} / \mathrm{mL}$ .
$5.31 M$
Chemistry 102
Chemistry 101
Chapter 3
Composition of Substances and Solutions
Solutions
Composition
Carleton College
Rice University
University of Maryland - University College
University of Kentucky
Lectures
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you can calculate the morality of a solution if we have, uh, percentage of our, uh, sulfuric acid, Our salute, um, and ar density of our solution remember more clarity as moles per volume, which is in leaders. And so h two s 04 has a mass of 98.78 grams per mole, and then it's a quiz. That means it's in water. So we need to add the mass of water just 18 0.15 grams per mole when I get that and a mass of 116 0.93 g per mole. Also, if you're a gas, it is 40% of that. So I'm gonna multiply by 400.4, and I get 46 0.44 grams. Next step is to convert that two moles. So 98.78 g equivalent toe, one mole. And when I divide that value for those values, I get 0.473 moles. So I'm gonna put that in my formula up here. Next step is to figure out our volume. So I take the mass of the entire compound. 116.93 grams and I divide that by the density, which is 1.30 57 g per milliliter. And then I multiply that by oops, a conversion factor, too. Convert from milliliters toe leaders and I get 0.89 leaders. And so I'll put that in my formula. When I divide those two values, I get a mill Arat e of five point 31 Mueller.
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