find-the-molarity-of-each-solution-which-solution-has-the-highest-molarity-the-highest-density-giv-3

Question

Find the molarity of each solution. Which solution has the highest molarity? the highest density? Give your reasoning.
a. 1.0 g KCl in 1.0 L water
b. 5.0 g KCl in 0.5 L water
c. 10.0 g KCl in 0.3 L water

David Collins · Accepted Answer

question Number four makes a connection between the density of the solution and the molar ity of the solution. So it wants to know which one has the highest mill, Arat E and which one has the highest density. Well, in this section you learned that the higher the mole arat e, the higher the density of the solution and vice versa, so you could calculate the density of each of these solutions and which everyone has the highest density will also have the highest morality. Or you could calculate the molar ity of these three solutions and which everyone has the highest polarity will also have the highest density. I went ahead and calculated the mole arat e of each of these solutions. 1 kg of potassium chloride, divided by its Moeller Mass will give us the moles well. Then divide that by the volume and leaders to get 134 Moeller k c l. If we have 5 g of potassium chloride, divide that by its smaller mass to get moles and then divide that by leaders to get more clarity, we get 50.134 Mueller K C l. And for the last one we have 10 g K c l in 100.3 leaders, we get 0.447 Mueller K C l. So this last one has not just the greatest mole arat e, but also the greatest density. Because of our previous discussion, we didn&#x27;t even have to carry out calculations. It is obvious that this is the solution that contains the largest mass in the smallest volume. Therefore, it must be the most dense and also the highest polarity.

William Mills · Answer

this question says that you have two solutions of chemical, eh? And then it says to determine which has the highest concentration of a formal arat e Which of the following must you know? And then it says there may be more than one answer. Do you need to know a. The mass Ingram&#x27;s of a In each solution be the molar mass of a see the volume of water added to each solution or d the total volume of the solution. So we know that polarity uppercase m equals moles per leader. So if you want to find the concentration, you need these two components. So let&#x27;s just cut under lesson, see if we would need these things to figure out what&#x27;s in here a the mass in grams of a in each solution. And this, of course, we would need to know In order to figure out number of moles, you need to figure out how many grams you have and then divide that by the molar mass. So we definitely need a the mass be Do we need to know the moler Massive, eh? Normally you would need to know the Moler Mass if you wanted to solve for the exact concentration. But since we&#x27;re making a comparison between a between two solutions of a the Moler Mass is the same for both solution since the same I saw you being dissolved. Therefore, we do not need to know the Moler massive A to make a comparison between the two solutions. We wanted to know the exact concentration we would. But since we&#x27;re doing comparison, we do not need to know the morning mass today. See, do we need to know the volume of water added to each solution? The voice of water added to a solid isn&#x27;t important. What&#x27;s important is what the final volume of the solution is. Some solids take up more space than others. So how much water you add is irrelevant. We just want to know what is the final volume. So we don&#x27;t need to know. Water added to see is not correct. But he says the total boy with the solution. So that&#x27;s this term here in the denominator of polarity, that&#x27;s the total volume of the solution. We do need to know that So we need to know d total volume. So then, if we new say, for example, the total volume of both the solutions was the same. It was one leader, but we knew that there were 10 grams of a in the speaker on the left and only five grams of it in the right. We would already know that the concentration was high. Concentration was higher in the beaker on the left because they had more salt or greater massive salt dissolved in it. So this question we need to know the mass of A and the total boy of the solution decide who has the higher concentration.

A. Elizabeth Hildreth · Answer

problem. 57 asks, given the following information how you would make each solution. So part a here asks how you would make 100 milliliters or 1.0 times 10 to the second milliliters off 100.5 Mueller. Potassium chloride. So remember that this capital m here, or, uh which stands for polarity is telling you, um, to think about how many moles of Salyut or the thing being resolved there are per one leader of solvent. All right, sorry. Solution. So in this case, um, it&#x27;s point 5/2 a mole of potassium chloride and one leader of solution Slowly. That we can figure out how to make this solution is simply by knowing by looking up the molecular weight. Yeah, shortened as mw of potassium cord. Um, you can never look this up on Google, or you can do the math based on tthe e atomic masses of each potassium and chloride and add those together. Um, but what? You get a 74.55 grams per mole. So what we know them is we have 0.5 moles of potassium chloride per one, leader of solution. We know that, um, we eventually want to figure out how many grams of potassium chloride we need to make this solution so we can plug in that molecular weight. We eventually want to figure out a reasonable number of grams to put in milliliters of solution leaders so we can convert from leaders two millimeters by knowing that there are 1000 milliliters per liter. And then we know that we ultimately want 100 milliliters or 1.0 times 10 to the second. No leaders of the solution. So once all of these other units cancel, what that leaves us with is the number of grams will ultimately have to add, um, to the beaker flask or whatever to make a 0.5 Moeller um, potassium chloride solution. So this ends up being is 3.73 grams of potassium chloride that you will want Thio, um, dissolve in enough water to total fellow leaders. Part be here asks how you would make 1.0 times 10 to the second grams off a 100.5 morale potassium chloride solution. So, unlike the capital in before, this is a lower case in, and what that means is the number of moles of Salyut per kilogram of solvent. So unlike before, the denominator here isn&#x27;t talking about the total sole solution, but the actual solvent dissolving your cell, You And so this particular math is a little bit more complicated because you have to do a little bit of extra algebra to figure out the proportions of Saul you insolvent that give you the proper mass of your whole solution while still giving you this 0.5, um, mole out ratio. So it&#x27;ll do. Here is I&#x27;ll set up a couple of different equations that we can solve, um, to figure out the number of grams of both Salyut and solvent that we need. So we&#x27;re going to call the mass of potassium chloride X and the mass of water the solvent here. Why, Mama Bull ultimately need to find is a mess of potassium chloride and water that gives us a total of 100 grands. The other equation that will need is, um uh, the actual morality equation. So I&#x27;m gonna call the number of moles of potassium chloride here capital A. We&#x27;ll call the number of kilograms of water this capital B here, and we know that ultimately our morality is gonna be this a over B. So what we can do here is take this part first, um, and do a little bit of conversion by using the molecular weight of calcium core or a potassium chloride. Sorry. So we know eventually that we want X number of grams of potassium chloride, and we know the molecular weight of taxing core. I admit that one mole, 74.55 grams. And so that gives us X over 74.55 We also know that, um, we have, um this relationship down here of X plus y equals 100. And so what I&#x27;m gonna do is I&#x27;m gonna set everything up so that its relative thio Why, um, in order to put back into this equation and solve for X. So, um, we know that X then is equal to 100 minus. Why? Then we can substitute that and for this equation here. Okay, so that&#x27;s the a portion of this. Now, be the number of kilograms of water. Um, we know that we have Why grams off water over here and we know that we eventually want that to be in terms of kilograms so we can set up, um, that conversion by knowing that there are 1000 grands per kilogram which gives us why over 1000. So, like I said, I have both of these terms now, um, in terms of why so what we can do first is plug in our A and B factors into this morality equation. So a is this 100 minus? Why? Over a 74.55 and that&#x27;s over power. Why are be component? That&#x27;s why over 1000 here, we can simplify this, but multiplying this whole this whole right hand side by 1000 over 74.55 to cancel out each of these denominators. Um And what? That leaves you with ISS 1000 signs, one under it minus Why? On top over 74.55 Why on the bottom, finally, we can plug in, uh, are known Morality is a 0.500 No. Wow. And we can solve for y. So what that gives us is why equals 96.41 grams, uh, water. And we can plug this back in to this equation over here to find that X, then are the number of grams of, um, potassium chloride is 3.59 grams. So what this means in terms of describing how to make the solution is that to make a 0.5 mole el calcium chloride solution, we have to mix 3.59 grams of calcium chloride with 96.41 grands off water. Somewhat simpler is this percentage by mass idea of, um, of concentration. And so what this means is that, uh, this is the number of grams. Uh, Saul, you per 100 grams of, um solution. So what this means is for every 100 grams of calcium chloride solution, there are five grams up your calcium chloride. So in this case, then like I just said five grams of calcium chloride for every 100 grands solution. We know in this case that we want to make 100 grams total of solution or one point cirie zero times 10 seconds. Um, grams, so we can multiply it by that? What that tells us is we need to mix five grams of calcium chloride then or potassium chloride. Sorry. Um, with 95 grams of water to solve it to give us 100 grams total of solution. Ah, 5% of which is potassium chloride.

Aashna Calidas · Answer

part a of this question were given to concentration values. The first step to solving this is to convert them to the same units, and I&#x27;m going to do this by converting 10,000 parts per 1,000,000,000 of potassium bromide into parts per 1,000,000. The conversion factor that needs to be used is one part per 1,000,000 for every 1000 parts per 1,000,000,000 and this equates to 10 parts per 1,000,000 of potassium bromide units like parts per 1,000,000 parts per 1,000,000,000 are both taken as a measure of mass per volume. Whereas malaria T is a measure of number of moles per volume. Since both of these values are given in terms of the same concentration of mass per volume, what we need to focus on is both of their Moeller masses and how they compare. Potassium iodide has a Moeller massive 166 grams per mole, and potassium bromide has the molar mass of 119 grams per mole. Now, since both of these have the same concentration in terms of mass per volume and potassium iodide has, ah, higher mass per mole. What we can conclude is that potassium iodide has fewer moles her the solution rather than potassium bromide. And this is true because my clarity is inversely proportional to Mueller Mass. When the concentration in terms of mass per volume is held constant in Part B, were given a similar problem. Were given potassium chloride and citric acid, both that 0.25% by mass. Again, we would need to compare their molar masses here. Potassium chloride has a molar mass of 74.55 grams, and citric acid has a molar mass of 192.1 to 4 grams. So since we&#x27;re given the same percent by mass and citric acid has a higher mass. What we can conclude is that citric acid must have fewer molds in order to match potassium chlorides percent by Maskin solution. Therefore, potassium chloride has a greater malaria. The overall

Catherine Lemar · Answer

say we have 100 mL, a variety of solutions. So we&#x27;ve got 1.1 Moeller and a C l. We have 0.1 Moeller Funny to see 03 0.1 Moeller in a O inch. Well, we&#x27;ve got 0.1 Moeller hcl. We want to dissolve calcium carbonate. We will be able to don&#x27;t dissolve most the most calcium carbonate in the acidic hydrochloric acid.

Problem

Find the molarity of each solution. Which solutio…

Problem 4 Easy Difficulty

Find the molarity of each solution. Which solution has the highest molarity? the highest density? Give your reasoning.
a. 1.0 g KCl in 1.0 L water
b. 5.0 g KCl in 0.5 L water
c. 10.0 g KCl in 0.3 L water

Answer

Related Courses

Living by Chemistry

Related Topics

Discussion

Top Chemistry 102 Educators

Lizabeth T.

Allea C.

Morgan S.

Karli S.

Chemistry 102 Courses

Liquids - Intro

Comparison Of Gases Liquids And Solids

Recommended Videos

Watch More Solved Questions in Chapter 15

Video Transcript

Angelica M. Stacy

Living by Chemistry

Lizabeth T.

Allea C.

Morgan S.

Karli S.

Liquids - Intro

Comparison Of Gases Liquids And Solids

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

Living by Chemistry

Lizabeth T.

Allea C.

Morgan S.

Karli S.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Lizabeth T.

Allea C.

Morgan S.

Karli S.

Angelica M. Stacy

Living by Chemistry