00:01
So we're given the following matrix and we want to find its multiplicative inverse if it exists.
00:06
So in order to determine the multiplicative inverse, we're going to rewrite this as the augmented matrix between this one and the identity matrix for a 3 by 3.
00:16
So the identity matrix for a 3 by 3 is just 1 -0 -0 -0 -0 -0 -0.
00:26
So if we rewrite this as the augmented matrix, we'll have 1 .7.
00:32
06, negative 2, 17, 3 ,02, 100, 010, 010, 0 .01.
00:45
And so the purpose of writing this matrix into this form is so that we can turn a into i using row operations, so that i will become a inverse.
00:58
So this is a, matrix a, and this is the identity matrix.
01:04
So let's start by using row operations to turn a into i.
01:11
So the first one will be to multiply the first row by negative 3 and added to the third row.
01:20
So if we do this, we'll have 1, 0, 0, 6, negative 3 times 1 is negative 3.
01:28
Oh, sorry, added to the third row, so the second row is the same, 1 and 7.
01:33
So this becomes 0, this stays as 0.
01:37
And our third row, so negative 3 times 6 is negative 18, negative 18 plus 2 is negative 16.
01:46
So the first two rows on the right hand side stay the same.
01:50
Our third row just becomes negative 3, 0 and 1.
01:56
The next row operation will be to multiply row 3 by negative 1 over 16.
02:06
So 1 .06 -10 for the first row, negative 2, 1 -7010 for the first row, negative 2, 1 -7 -0 for the 1.
02:15
Second row 0 -0 -1 negative 3 over 16 0 and 1 over 16 sorry negative 1 this is positive 3 over 16 now we're going to multiply row row 3 by negative 6 so negative 6 times row 3 we're going to add that to row 1 so the first the third row and second row stay the same 3 over 16 0 1 over 16 0 1 over 16 010...