00:01
So we want to find the multiplicative inverse of the following matrix.
00:05
And to do so, we're going to augment it with the inverse.
00:10
So the resulting matrix will be 1, 2, negative 1, negative 3, 4 and 1, negative 2, negative 4, negative 5.
00:21
And the identity matrix for 3 by 3 is just 1, 0 ,0, 0 ,01.
00:30
And by using row operations, we want to transform the left -hand side of the matrix into the right -hand side.
00:38
And in doing so, this left -hand side will give us the inverse.
00:43
In other words, we want to transform a into i so that i becomes a -inverse.
00:52
So the first step to do so will be to switch r3 with r2.
01:01
So we'll have 1, 2, negative 1, negative 2, sorry, negative 2, negative 4, negative 5, negative 3, 4, and 1.
01:20
And the right hand side will have 1, 0 ,0, 0 ,01, and 010.
01:28
Now we're going to multiply r1 by negative 5 so that we can add it to r2.
01:37
To find any new r2, so the first and third row, the same the second row just becomes negative 7 negative 14 and 0 and this constant right here just becomes negative 5 0 and 1 now the second the following step will be to multiply r1 by 3 and added to r3 so we'll have 1 to negative 1 negative 7 negative 0 0 10 and negative 2 on the right hand side will have 1 0 -0 -0 -0 -0 -1 3 -0 then we're going to multiply r3 by negative 1 1 half and we're going to add it to r1 so r1 just becomes 1 negative 3 0 negative 1 1 1 1 1 1 1 0 0 and the rest is the same negative 7 negative 7 negative 14 0, negative 5, 0 and 1, 0, 10, negative 2, 3, 1, 0.
03:23
Now we're going to multiply r1 by 7 to get rid of this 7 over here, and we're going to add it to our 2 to do so.
03:34
So we'll have 1, negative 3, 0, 010, negative 2, negative 1 over 2, negative 1 over 2, 0 ,0, 310, and the 2.
03:49
Second row just becomes 0, negative 35, 0, negative 16 divided by 2, and negative 7 divided by 2, sorry, and 1...