00:01
Okay, so for this exercise, we've got that for the part a, we have this vector v that is 1, minus 1, and 2.
00:16
And we want to know is a vector v -tilda that is given by minus b divided the norm of.
00:28
So let's start by computing the norm of the vector v.
00:32
That is just the square root of 1 plus 1 plus 2 square.
00:40
So this at the end is just the square root of 6.
00:46
Then to compute the v -tilda here is just taking minus 1 divided the norm, that is the square root of 6, and the vector b, that is 1, minus 1, and 2.
01:06
And that's it.
01:07
But we can make it one more step by just putting the minus inside the vector.
01:17
So here we got the square root of 6, minus 1, 1 and minus 2...