00:01
So in this problem, we're first being asked to write an equation that will allow us to find the nth term in this particular arithmetic sequence where a sub 1 is the square of the 2 and d is also the square of the 2.
00:12
Well, remember, our general formula is a sub n equals a sub 1 plus the quantity of n minus 1 times d.
00:21
So what we'll do is substitute the square of the 2 in for a sub 1 and the square of the 2 in place of d.
00:27
So when we do this, we're left with a sub n equals the square of the two plus the quantity of n minus 1 times the square of the 2.
00:37
And now we just have to simplify.
00:39
Well, to do this, i'm going to first distribute the square of the 2.
00:44
So we'll be left with a sub n equals the square of the 2 plus the square of the 2 n minus the square of the 2.
00:53
Well, next we have to combine our like terms.
00:55
But the square of the two minus the square of the two is zero...