00:01
So for this problem, we'll be taking advantage of exclusion, inclusion, for three elements.
00:06
We'll have a1, a2, union, a3, we'll have a number of elements, sort of little bars.
00:15
We'll have elements of a1, number of elements of a1, plus the number of elements of a2, plus for a3, minus, and then we're going to do the intersections between each one.
00:34
I'm only slightly wishing i did abc.
00:39
We'll have minus 82 intersect a3.
00:45
And we'll have plus the intersection of all three of all.
00:50
And so for some of these, you don't want to think too much harder than you actually need to.
00:54
And i'll start by saying that this should be intersection.
00:58
Sorry about that.
01:00
I'll start that off with part a.
01:02
So we know each element has 100 in them, and we know that it's pairwise disjoint.
01:07
So there's nothing in common.
01:08
So the rest of this doesn't even matter.
01:10
We're just counting number of a1 plus the number of a2 plus the number in a3.
01:15
So a is just 300...