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Numerade Educator



Problem 5 Easy Difficulty

Find the numerical value of each expression.
(a) $ sech 0 $
(b) $ \cosh^{-1} 1 $


(a) $\operatorname{sech} 0=\frac{1}{\cosh 0}=\frac{1}{1}=1$
(b) $\cosh ^{-1} 1=0$ because $\cosh 0=1$


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Video Transcript

we know the form that we're gonna be using as to over eat of the exposed to the negative axe. Plug in zero. This is to over one plus one, which is to over two, which is one we know we're gonna have the natural log of acts, plus the square root of X squared minus one. This is the natural of one which you know is simply zero.