00:01
We're asked to plot, find the asymptotes and the period of this function here, minus 3 tangent of x over 3 minus pi over 3.
00:13
So to find the period, we need to set, we're scaling the x, x, x is by 1 3.
00:20
So the period of tangent is pi, is pi.
00:23
So the period of this function will be 3 pi because we have x over 3 here.
00:34
So we can see here that i've actually plotted this from minus pi over 2 to positive 3 pi over 2.
00:45
So that's one period.
00:47
Here's one period.
00:49
Well actually i plotted it actually over 2 periods.
00:51
Sorry i plotted it from minus 3 pi to 3 pi because this is two periods of the tangent function now now we have then to find the ascentotes remember that the tangent function tangent equals sine over cosine so the asymptotes are when cosine is zero so that's when x over 3 minus pi over 3 equals pi well let's see here let's do it this way we can say plus or minus plus or minus pi over 2 plus 2 and pi so let's see here we can have and we can rewrite this as let's see this is multiplied through by 3 you get x equals pi plus or minus pi over 2 plus 6 n pi so what does that tell us well if we say n equals 0 we know we have one one one uh one acinote and let's see here when um we know we have one um one one one uh one acetote and let's see here when um we is this right? oh no, i forgot to multiply that by three.
02:37
There, we need a three in there.
02:39
Okay, so let's see.
02:41
When nx0, we have an acentote at minus pi over two...