Question
Find the points on the curve $x^{2}+y^{2}-2 x-3=0$ at which the tangents are parallel to the $x$ -axis.
Step 1
The given equation is $x^{2}+y^{2}-2 x-3=0$. Differentiating it, we get $2x + 2y \frac{dy}{dx} - 2 = 0$. Show more…
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