Question
Find the points $(x, y)$ at which the curve has: (a) a horizontal tangent: (b) a vertical tangent. Then sketch the curve.$$x(t)=\cos t, \quad y(t)=\sin 2 t$$
Step 1
The derivative of $x(t)$ with respect to $t$ is $dx/dt = -\sin t$ and the derivative of $y(t)$ with respect to $t$ is $dy/dt = 2\cos 2t$. Show more…
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