Find the potential difference between points- A and -B in Fig. 26- 5 if R is 0.70 Ω. Which point

Find the potential difference between points- A and -B in...

Key Concepts

Electric Potential Difference

Electric potential difference, often simply called voltage, is the measure of the work done per unit charge as a charge moves between two points in an electric field. It represents the energy difference between the points and is a fundamental concept in understanding how electrical circuits drive current through components.

Ohm's Law

Ohm's Law is a foundational principle in electrical circuits, stating that the current through a resistor is directly proportional to the voltage across it and inversely proportional to its resistance (V = IR). This relationship is essential for calculating voltage drops in resistive elements and is extensively used in circuit analysis.

Resistive Circuit Analysis

Resistive circuit analysis involves understanding and calculating how voltage is distributed across the various resistive elements in a circuit. By applying principles such as Ohm's Law and Kirchhoff’s Voltage Law, one can determine the potential differences between various points in the circuit, which is crucial for identifying which parts of the circuit are at higher or lower potential.

Transcript

00:01 Hi in this given problem here is a segment of our closed circuit which is having a battery connected to it having a potential 6 .0 volt then a resistor of value 2 .0 oom after which another battery another cell joined with opposite polarity having a voltage 9 .0 volt then one more resistance which is missing and in the problem value is given as 0 .70 om here this terminal is marked as b and this is a the current passing through this series segment is 3 .0 ampere and as we know current remains the same in series so the same current will be passing through out this branch.

01:05 Now here we have to find the potential difference between a and b so the final potential will be considered to be at b and initial is at a.

01:19 So we have to find v b minus b.

01:23 So to find it we use the concept whenever we consider a branch adding a current in the direction of current wherever whenever we get the resistance the potential drop across it i into r that is always subtracted potential drop as it is dropped so it is subtracted from the potential at the initial point suppose it to be va then if the battery is in this bullet from negative to positive it's emf let it be even that is always added and if we get a battery with opposite polarity means here this is plus this is minus and this is e2 this is e2 so this emf is always subtracted to reach up to the final potential at the opposite terminal if this is a this is b this was a then we will get it to be b so using this concept here, we start from the terminal a.

02:40 Suppose its potential is va, then va and it will be minus 6 .0 volt.

02:48 Then potential drop 3 into 2, minus 3 into 2 using woms law.

02:55 Potential drop is given as i into r.

02:57 Then plus 9 .0 volt.

03:00 Then again minus current 3 ampere...

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