00:01
We want to find the radius and the interval of convergence for this power series, so we'll use the ratio test.
00:08
So you take the limit as in goes to infinity of the n plus first term.
00:13
And since we're taking the absolute value of this ratio that we're going to write here, the n plus first term divided by the nth term, we don't have to put the minus 1 to the n in there because they're going to cancel that anyway.
00:28
X to the n plus 1 over the cube root of n plus 1.
00:33
Over x to the n over the cube root of n.
00:39
Okay, so invert and multiply the bottom one.
00:43
Limit as in goes to infinity, x to the n plus one, cube root of n plus one, times cube root of n over x to the n.
00:59
Okay, so now i'm gonna rewrite it and put the similar pieces together, x to the n plus one over x to the n, cube root of n over the cube root of n plus one.
01:16
All right, you have n plus 1, x is on the top, and n of them on the bottom that leaves one of them on the top.
01:24
And then this is the cube root of n over n plus 1.
01:30
All right, so the limit of the product is the product of the limit.
01:33
So we take the limit of x, so we get x, and then we take the limit as in goes to infinity of the cube root of n over n plus 1.
01:45
So in fact, we can just go all the way into the cube root and take the limit.
01:57
Okay, so that's infinity over infinity.
01:59
If you love patel's rule, you get 1 over 1, so that limit is 1.
02:02
So you get the absolute value of x.
02:05
And then you set it less than 1 because the ratio test says, if that ratio is less than 1, this series is convergence.
02:15
Okay, so that means our radius of convergence is 1.
02:22
All right, so we know for sure that it's convergent between 1 and negative 1...