00:01
Will given the series of the form minus 3 power n, dividing by n times quix n times x b bhawn and and goes from 1 to infinity.
00:12
Here i am going to use the ratio test here and in the ratio test i need to compute the limit of the am plus 1 over a n and yes to infinity and then we get am plus 1 so because of option values don't need to worry about this minus here.
00:36
So we have the 3 bar and this 1, xbord n plus 1, dividing by n plus, i will write this one as an n plus 1 power of the 3 out of 2.
00:48
And now i divided by an so it will be multiplied by the reciprocal.
00:54
So am 3 out of 2 over the 3 bell n, x power n.
00:59
Here we see we can cancel the 3 bar and with this power, x power, x power, x, and we can cancel the and we dispel power as well.
01:05
And we can group this 2 here into the same power of 3182.
01:09
And we bring the 2 constant here outside the limit.
01:13
Therefore we have the 3 times absolute x times the limit of the n over n plus 1...