Question
Find the ratio of the energy of a 21 -cm photon to the energy of an electron shifting from the second energy level of hydrogen to the ground state, which produces a photon of 122 -nm wavelength.
Step 1
We can use the formula E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. Plugging in the values, we get: E = (6.626 x 10^-34 J·s)(3.00 x 10^8 m/s)/(21 x 10^-2 m) E = Show more…
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