Question
Find the rational zeros of the polynomial function.$$f(z)=z^{3}+\frac{11}{6} z^{2}-\frac{1}{2} z-\frac{1}{3}=\frac{1}{6}\left(6 z^{3}+11 z^{2}-3 z-2\right)$$
Step 1
The rational root theorem states that the possible rational zeros of a polynomial function are the factors of the constant term divided by the factors of the leading coefficient. In this case, the constant term is -2 and the leading coefficient is 6. Show more…
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Finding the Rational Zeros of a Polynomial In Exercises $103-106,$ find the rational zeros of the polynomial function. $$f(z)=z^{3}+\frac{11}{6} z^{2}-\frac{1}{2} z-\frac{1}{3}=\frac{1}{6}\left(6 z^{3}+11 z^{2}-3 z-2\right)$$
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In Exercises 103 - 106, find all the rational zeros of the polynomial function. $ f(z) = z^3 + \dfrac{11}{6}z^2 - \dfrac{1}{2}z - \dfrac{1}{3} = \dfrac{1}{6}(6z^3 + 11z^2 - 3z - 2) $
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