00:01
Okay, based on the remainder theorem, we know the remainder rnx is given by the m plus 1 -third derivative as i'm constant c over m -plus -1 factorial times x to the m -plus -1.
00:19
Here, c is between the center is 0 and the x.
00:28
Okay, so we need to figure out what's this m -plus -1 -dur -durative.
00:33
So let's take some derivative to see what happens.
00:39
So the first of the derivative is given by 1 minus x to be minus 2.
00:44
The second of the derivative, 2 times 1 minus x to be minus 3.
00:51
Third of the derivative, 2 times 3 times 1 minus x to me minus 4.
00:59
So in general, the n plus 1 third of the derivative will be n plus 1 factorial.
01:09
Times 1 minus x to the minus m plus 2.
01:14
So we can plug in c into this derivative.
01:20
Then we can rewrite the rnx to be m plus 1 factorial times 1 minus x to the minus m plus 2 divided by m plus 1 factorial times x to the n plus 1.
01:39
It should be c here...