00:01
In this exercise, we first want to find the derivative of a function fx equals to minus 5 thirds x squared plus 2x plus 2.
00:23
And the derivative of this function is minus 5 thirds times 2x, the derivative of x squared equals 2x, plus 2.
00:37
And the derivative of the nasa term, which accounts in just zero.
00:44
Let's simplify this expression as minus 10 thirds x plus 2.
00:52
And next we want to evaluate the derivative at x equals minus 1.
01:04
So we just substitute x with minus 1, which equals 10 thirds plus 2, which is 10 thirds plus 2, which is 16 over 3.
01:24
And next, we want to find the equation of the 10 .9 at the point minus 1 minus 5 3rd.
01:34
We can also write this equation as y minus 5 3rd equals 16 over 3, which is just as a slope at the point...