00:10
We have this function, and we want to find the slope of line tangent to the function, the x value, negative 1.
00:17
So our definition of instantaneous velocity here is also the slope of the function.
00:26
So it'll be slope of g of x plus h minus g of x over h.
00:35
Our x value is negative 1, so this becomes g of x.
00:40
Of it can be negative 1 plus h or h minus 1.
00:45
Minutes g of negative 1 all over h.
00:49
Okay, let's figure out g of negative 1 first.
00:53
It would be 2 times negative 1 squared plus 5.
00:58
So that's 2 plus 5 or 7.
01:01
And then let's find g of h minus 1, which will be 2 times h minus 1, which will be 2 times h minus 1 squared plus 5.
01:13
We have to foil the h minus 1, and i'm going to do a shortcut for that...