00:01
The big idea in this problem is what the tangent slope is by definition.
00:06
So what i've written in the box is that definition.
00:10
To find the tangent slope at a particular x value c, we're going to take the limit as h approach to zero.
00:17
H is like the run of the slope.
00:21
Of the function evaluated at c plus h minus f of c, that's the change in y or the rise, over c plus h.
00:32
Minus c, which is really just h.
00:34
That's the run.
00:35
So what we're going to do for our function in question is calculate this for any value c, and then we can use that to find the slope of the tangent line at particular choices of x.
00:50
So let's compute the tangent slope using our definition.
00:56
It's limit as each approach of our function evaluated at c plus h.
01:00
So we'll have c plus h squared minus 1.
01:04
Minus our function evaluated at c, that's c squared minus 1, all divided by h.
01:18
So let's now try to get rid of these brackets.
01:21
We have c plus h squared minus 1.
01:23
This negative sign can distribute to be negative c squared plus 1, all over h.
01:29
We immediately see these ones offset, negative 1 plus 1 is 0...