Question
find the solution set for each system bygraphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations.$\left\{\begin{array}{l}x=(y-2)^{2}-4 \\ y=-\frac{1}{2} x\end{array}\right.$
Step 1
The first equation, $x=(y-2)^{2}-4$, is a horizontal parabola, and the second equation, $y=-\frac{1}{2} x$, is a straight line with a slope of $-\frac{1}{2}$. Show more…
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Find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. $$ \left\{\begin{aligned} (y-2)^{2} &=x+4 \\ y &=-\frac{1}{2} x \end{aligned}\right. $$
Conic Sections
The Parabola
Find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding all points of intersection. Check all solutions in both equations. $$\left\{\begin{array}{r} 4 x^{2}+y^{2}=4 \\ 2 x-y=2 \end{array}\right.$$
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find the solution set for each system by graphing both of the system’s equations in the same rectangular coordinate system and finding all points of intersection. Check all solutions in both equations. $$\left\{\begin{array}{c} 4 x^{2}+y^{2}=4 \\ 2 x-y=2 \end{array}\right.$$
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