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Find the speed of light in (a) water, (b) crown glass, and (c) diamond.

a. $2.25 \times 10^{8} \mathrm{m} / \mathrm{s}$

b. $1.97 \times 10^{8} \mathrm{m} / \mathrm{s}$

c. $1.24 \times 10^{8} \mathrm{m} / \mathrm{s}$

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our question asked us to calculate the speed of light in three different mediums. The first medium is water where the index every fraction I write is in sub W is 1.333 The second medium is glass. The index of refraction in sub D is 1.52 and the third medium is diamond in sub D is equal a 2.419 for its index of refraction. Well, the, uh, index of refraction. So we'll go ahead. Mark, this is part, eh? End in general is equal to the speed of light divided by the velocity and the velocity, then would be the velocity of light in that medium. So it's the ratio of the speed of light in a vacuum, see, which is three times 10 to the eight meters per second to the speed of light in that medium, the so using that equation and rearranging to find velocity, we confined the velocity of the speed of light, and water is equal to the speed of light in a vacuum divided by the index of refraction. Here it's the index of refraction, of water plugging those values and its expression we find that this is equal to two 0.25 times 10 to the eight meters per second. Okay, Linkenbach said it is our solution to the question part B. We're gonna do the exact same thing. Except this time we're doing it for glass. So the velocity of glass or excuse me? The velocity of the speed of light in glass is equal to speed of light, divided by index of refraction of plus replacing those values into this expression, we find that this speed is 1.97 times 10 to the eight meters per second Boxing gyms or solution for part C. Remember, some more room will start a new page in do part. Excuse me, I was a solution for R B. Here's the solution for part C. Same expression. This time we're just using the values for diamond. So the speed of light and diamond is the speed of light divided by the index of refraction of diamond, and this is equal to 1.24 Thompson of the eight meters per second. Linkenbach said It is our solution for part C.