Question
Find the standard form of the equation of the circle with the given characteristics.Endpoints of a diameter: (-6,0) and (0,-2)
Step 1
The midpoint of two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$. So, the center of the circle is $\left(\frac{-6+0}{2}, \frac{0+(-2)}{2}\right) = (-3, -1)$. Show more…
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