For (a), we add $(1 \mathrm{AE})_{16}$ and $(\mathrm{BBC})_{16}$, which gives us $(D 6 A)_{16}$.
For (b), we add $(20 \mathrm{CBA})_{16}$ and $(\mathrm{A} 01)_{16}$, which gives us $(216 B B)_{16}$.
For (c), we add $(\mathrm{ABCDE})_{16}$ and $(1111)_{16}$,
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