We have:
$$ \frac{1}{1^{4}}+\frac{1}{2^{4}}+\frac{1}{3^{4}}+\frac{1}{4^{4}}+\frac{1}{5^{4}}+\frac{1}{6^{4}} $$
To find the sum, we can use the formula for the sum of a finite geometric series:
$$ S = \frac{a(1-r^n)}{1-r} $$
where $S$ is the sum, $a$ is the
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