Find the sum to $n$ terms of each of the series in Exercises.
$$
3 \times 8+6 \times 11+9 \times 14+\ldots
$$

Answer

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Precalculus

NCERT Class 11 - Math

Chapter 9

Sequences and Series

Section 4

Arithmetic Progression (A.P.)

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Video Transcript

number six. And which And we have to find the sum of thing into eight plus six into 11 plus 19 to 14. Plus up to in terms. So first of all let us find the will of A. N. It will be three. And and to this is eight so it should be three and plus five. Okay So s in there is some will be equal to from an equal to one to end. This is three and a square. That is nine in the square. Yeah plus 15. And so nine in the Squire. I was 15. And okay I'll just use distributive law to distribute this submission and Squire players 15 submission of N. N. Equal to one to end from nine. And and bless one 20 plus one by six. Because this is the some of square of first N. Natural numbers and this is the summer first and natural numbers and in two and plus one by two. Let us take this is 33 times two times little state three and plus one. Okay. Okay. Okay. Okay. Three and in two and Pleasant by two as common we will be having to win plus when bless 15, wow. Okay. Is this good? Sorry? It will be because we have always taken three so it will be five not 15 five. So we have three and and Pleasant by two in 22 N. Plus six. So this is three N. And plus one. Let us take two as common so and plus three by two and you will get cancelled out. Sn will be equal to three and and plus one and then plus three. This should be the answer. Thank you.

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