Question
Find the tangent to the curve $x^{3}+3 x y+y^{3}+x^{2} y=0$ at the origin.
Step 1
The given equation is $x^{3}+3 x y+y^{3}+x^{2} y=0$. Differentiating it, we get: \[3x^{2}+3y+3xy\frac{dy}{dx}+3y^{2}\frac{dy}{dx}+2xy+x^{2}\frac{dy}{dx}=0\] Show more…
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Key Concepts
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