Question
Find the Taylor series expansion at $x=0$ of the given antiderivative.$$\int \frac{1}{1+x^{3}} d x$$
Step 1
Step 1: First, we rewrite the integral of $\frac{1}{1+x^{3}}$ as the integral of $\frac{1}{1-(-x^{3})}$. Show more…
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