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Hello, we are looking at chapter 12, section 5, problem number 21.
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And we are to try to find the taylor series expansion for the given function, f of x equals natural log of 1 plus 2x to the 4th, and give the interval of convergence.
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So i'm going to start with the elementary series, taylor series expansion that most resembles this, which would be our basic natural log expansion, which is the natural log of 1 plus x.
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And that expansion starts with the first term x.
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And then we have minus x squared over 2, and then plus x cubed over 3, minus.
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So we have an alternating series.
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And if we go to the nth term, we can write that as negative 1 to the n to account for the alternating, and then we have x to the n over n.
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And this is true for the interval of negative 1 less than x, less than 1.
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So we need to change this.
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This is a pretty quick change.
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We can simply replace this x with 2x to the 4th in one shot.
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So we're going to write that we're going to replace every x with 2x to the 4th.
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So that we'll wind up with the expansion for the natural log of 1 plus 2x to the 4th.
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And so we're going to shoot through our elementary series, and everywhere we see an x, we're going to replace it with 2x to the 4th.
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So starting with that original x for the first term.
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So we'll say 2x to the 4th.
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Oops, minus...