00:01
Hello everyone, in the following question we have to find this by northern and by thavening equivalent.
00:07
Firstly we will apply method a to find zn.
00:11
If we have to find the value for zn, we will consider the following circuit.
00:17
If we have to find the value of jn, we will consider the folding circuit.
00:21
In this circuit we will say that zn, we will say that zn is equal to jand.
00:28
This can be as 10 plus j20 is parallel to minus j10.
00:35
This can be written as 10 plus j20 minus j10.
00:41
In the denominator we will write j20 minus j10.
00:46
We will solve this equation.
00:47
We will get 10 minus j20.
00:50
We will get this 22 .36 into 22 .36 into minus 63 .43 .43.
01:00
Degree o.
01:01
This is the value for jdn.
01:03
Now we have to find the value for bth.
01:07
Now we have to find the value for bth.
01:10
We will consider this the circuit.
01:12
We will consider the folding circuit.
01:14
Now we have to find the value for vth.
01:17
We will solve this equation.
01:19
For vth, we will get the value as minus j10.
01:24
In the denominator we will write minus j20 minus j10.
01:28
Here we will write 15...