Question
Find the two $x$-intercepts of the function $f$ and show that $f^{\prime}(x)=0$ at some point between the two $x$-intercepts.$f(x)=x^{2}-x-2$
Step 1
We do this by setting the function equal to zero and solving for $x$: \[x^{2} - x - 2 = 0\] This equation can be factored into: \[(x - 2)(x + 1) = 0\] Setting each factor equal to zero gives us the x-intercepts: \[x - 2 = 0 \Rightarrow x = 2\] \[x + 1 = 0 Show more…
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