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Find the unknown.$$(4 y+7)^{2}+36=0$$

$$\frac{-7 \pm 6 i}{4}$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

McMaster University

University of Michigan - Ann Arbor

Idaho State University

Lectures

01:58

Find the unknown.$$(6 …

01:05

Find the unknown.$$y^{…

00:36

01:29

Find the unknown.$$6 y…

00:24

01:45

Find the unknown.$$(2 …

02:26

Find the unknown.$$\fr…

01:59

Find the unknown.$$(y-…

Find the unknown.$$2 y…

02:08

00:47

Find the indicated derivat…

00:41

Solve each equation.$$…

01:23

$$\text {Find } D_{x} y$$ …

this problem is asking us to solve for why so four y plus seven squared plus 36 is equal to zero. So the first thing you want to do is get this squared term by itself, which can be done by subtracting the 36 over. And the quick statement that I need to mention is it's impossible for us to square a real number, whether it's positive or negative and get a negative, because all numbers square there either zero or positive. So So we're getting a non real solution on this problem. But we have a way around it because if we asked somebody to square a negative square root and negative because that's how we undo the square, we just write plus or minus the square to 36 to 6 I that's a way around. I guess that that non real solution that would have been the case, Um, so now what we can do is we can solve for Y by just subtracting seven over, and because that's a real number, we always write the real part in front of the imaginary part. We still have four y on the left side and then we just solved for y by dividing the four over, and most people just rewrite. This answer is negative. Seven plus or minus six I all over four, and that's it. Just for simplicity. Some people might rewrite this as negative seven force because 65 before would reduce to three halves. And don't forget about that, I But yeah, this is a complex number. It's a complex route instead of a a real root.

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