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Find the unknown.$$5 y^{2}+12=3 y^{2}-24$$

$$\pm 3 \sqrt{2 i}$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

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Lectures

01:58

Find the unknown.$$(y-…

01:59

Find the unknown.$$(2 …

02:26

Find the unknown.$$\fr…

00:36

Find the unknown.$$2 y…

Find the unknown.$$y^{…

00:24

01:05

02:08

03:30

find $d y / d x$$$y=(2…

06:23

Find $d y / d x$$\frac…

02:09

Find $d y$$$y=x^{3}(2 …

01:00

Find $d^{2} y / d x^{2}$.<…

So when you read here, So here you want to find for why First thing we want to do is put the Y on one side of the equation and the numerical values on the other. So we're going to do minus three y square. Yeah, to end up getting to buy square Plus 12 is equal to this. Cancels out negative 24. When a subject 12 from both sides to get to I square, this cancels out, is equal to negative 36. And then we wanted to fight this whole thing by two. And we get why square is equal to negative one 16, 8 negative 18. And let's take a look on the right here where X Square is equal to negative one and we want to find for X X becomes plus minus. I were eyes imaginary number. So knowing that we're going to square root both sides, we get why is equal to square of negative one times the square of nine times the square root of two. So we get Y is equal to plus minus three squared of two. I

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