Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

Find the unknown.$$(6 y-2)^{2}+9=41$$

$$\frac{1 \pm 2 \sqrt{2}}{3}$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

Campbell University

Oregon State University

Harvey Mudd College

Lectures

01:29

Find the unknown.$$6 y…

01:50

Find the unknown.$$(4 …

01:45

Find the unknown.$$(2 …

01:05

Find the unknown.$$y^{…

00:36

01:59

Find the unknown.$$2 y…

02:26

Find the unknown.$$\fr…

00:24

02:08

01:58

Find the unknown.$$(y-…

01:35

Solve.$$y^{2}+6 y+9=0$…

00:47

Simplify.$$4+6(y 2…

02:17

Solve.\begin{aligned}<…

so we need to solve for y in this problem, six wide minus two squared plus nine is equal to 41. So the first thing that you want to do is get the squared term, the entire thing being squared by itself, which can do by subtracting this nine over. Um, well, 41 minus nine is 32 and on the left side. Just leave that alone. Because now that it's all by itself, you can undo the square by square, rooting both sides and how I like to do this problem is, first of all, the square root. Cancel with that square. So on the left side just left with six wide minus two on the right side, I like to actually factor tree that down as 16 times two and then 16 breaks down is four and four, so you can bring that four in front. This is just how I like to explain the simplest radical form I know. Some other teachers prefer rewriting. Route 32 is Route 16 times route to and the square to 16 is four. Um, so different. Different preferences for different people. So now what you can do is solve for Y by first adding the two to the right side and a lot of pretty much every math. Futural. Right, Um, the whole number in front of the radical. But we cannot combine them together because they're not like radicals and then divide both sides by six. Now, as you go to simplify this answer, I hope you realize that all of the whole numbers are divisible by two. So that's what you want to do is simplify your answer by dividing each piece by two. Well, to divide by two is 14 divided by two is two. You can't change the radical and six divided by two is three. So this is the best answer for this problem, Yeah.

View More Answers From This Book

Find Another Textbook

Numerade Educator

02:00

Find the unknown.$$(2 r-3)^{2}-24=0$$

03:30

In each of the following exercises, solve the given inequality.$$\frac{1…

01:42

Rewrite the equation in the form $a x^{2}+b x+c=0,$ with $a > 0,$ and the…

04:21

Solve for the unknown, and then check your solution.$$2 w-7=5 w-7$$

01:55

In each of the following exercises, solve the given inequality.$$(3-4 x)…

01:11

Find equation for the given line.A vertical line passing through $(-1,8).$

01:04

02:10

Find the unknown.$$\frac{3}{8}(x+7)^{2}+\frac{3}{4}=\frac{15}{2}$$

Determine if the given set is a function.$T=\{((2,-1),(3,-1),(5,-1),(6,-…

01:06

Find the unknown.$$x^{2}+25=0$$