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Find the unknown.$$\frac{3}{4} y^{2}+24=0$$

$$\pm 4 \sqrt{2} i$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

Baylor University

Idaho State University

Lectures

01:59

Find the unknown.$$(2 …

00:24

Find the unknown.$$y^{…

00:36

Find the unknown.$$2 y…

02:08

Find the unknown.$$\fr…

01:58

Find the unknown.$$(y-…

01:05

01:51

find $d y$.$x y^{2}-4 …

02:28

Find $d y$$$x y^{2}-4 …

01:41

Solve.$$3 y^{2}+8 y+4=…

00:47

Solve the equation by fact…

00:57

Use factoring to solve the…

02:32

Find $d y / d x$$4 x^{…

Okay, so we're asked to find the unknown in this problem in the unknown as why and so we're trying to get why by itself, it's advantageous to get why squared by itself first. So the first thing I would do is subtract 24 over kind of nice zero months. Anything is just the negative of that piece. I'm gonna leave this three for so long. And I was always taught to get rid of a fraction we multiply by the reciprocal. Uh, yeah, You could divide both sides by 3/4 but divided by three forces, the same thing is multiplied by four thirds. You can see the forwards would cancel. Here. The threes are canceled, so you are left with y squared. Um, I would do this in my head by thinking about 24. Divided by three. First is eight times four gives me negative 32. This is how I would do the math. In my head, you can use a calculator. Times four divided by three is negative. 32 um, so now there's a to solve the square problem. You square root both sides now. Depending on your professor, they might want you to recognize that there's no real solution because you cannot square root a negative and get a real answer. But based off of everything else that I've seen, they're okay with imaginary numbers. Plus or minus the square root of negative will give you an imaginary so high in there I would actually show the work. With that 32 breaks down as a yeah, four and eight, you can break down eight again as four and two. Um, Now I like to do it this way. Where you have you can bring a pair of numbers in front. So we're looking at four I route to If you're confused on what I'm doing, what I'm technically doing, I'll do this off to the side is I'm practicing the square to 32 which is equal to a little equal sign the square root of 16 times the square root of two, and the square to 16 we know is four route to. Otherwise you can look for pairs of numbers to bring in front. You need to plus or minus because there are two answers and you need the eye for the negative numbers. That's your answer for why mhm

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