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Find the unknown.$$(x-2)^{2}=9$$

$$-1,5$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

Missouri State University

Campbell University

Oregon State University

Baylor University

Lectures

01:44

Find the unknown.$$(x+…

00:33

Find the unknown.$$x^{…

00:47

Solve for the unknown vari…

00:50

00:32

01:30

Find the unknown.$$(x-…

00:58

Find the unknown.$$8 x…

00:09

Solve.$(x-2)^{\frac{2}…

Solve.$$x^{2}=-9

01:09

Solve $x^{2}+2 x=9$.

02:17

Find the unknown.$$\fr…

So this, uh, solving this problem is set up really easily because it's already a perfect square was behind. Um So that's the first thing when you have a problem like this is you want to make sure that the square it is all by itself so you can undo the square by square, rooting both sides, Um, and that gets rid of the square. It's the inverse operation now. When you do that, make sure that you write out that the square to nine is plus or minus three, and then the only other thing is to solve for X solve for the unknown By adding the two over and now, it's very uncommon that a teacher would let you leave your answer as to plus or minus three because they would expect you to write out, because the answers are whole number. Answers. That two plus three would be five and two minus three would be negative one. So those are your two values your ex, and you can double check their right by plugging them back into the original. You know, if X is five five minus two is three squared is positive night, so that's good again. Negative one minus two is negative. Three. When you square a negative, you do get a positive nine. So this is good.

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