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Find the unknown.$$(x-3)(x+2)=14$$

$$-4,5$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

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Lectures

02:14

Find the unknown.$$(x+…

02:30

Solve.$$(x-3)(x+2)…

00:57

Solve.$$x 2=14 x+3$$

01:10

Plz answer this question q…

00:19

Find the value of $x$$…

00:22

Find the value of $x .$

00:52

Solve each equation.$$…

04:27

Solve.$\frac{3}{x}+\fr…

00:24

00:23

Alright, We're asked to find the unknown of this problem. X minus three times X plus two is equal to 14. So the way I would do this problem because I would start by distributing this X in here. So we're looking at X squared plus two x and distribute that three year old two x minus three x will be negative. One x and they have three times two give me negative six still April to 14. Oops, because my next step would have been to subtract the 14 over. So now we're looking at, uh, zero. And the reason why you want to subtract that 14 over is now you have a quadratic and this quadratic is factory. There's factors of 20 negative 20 that had to be negative one. Uh, those numbers are five and four, and in order to make a negative one, is to make it at five Negative Negative. Five plus four, uh, 95 times four is negative 20 which is woven one and negative. Five plus four is negative one. So that means that we can factor this as X minus five X plus four, and, uh then from there you can use the zero product property that either X minus five equals zero or X plus four equals zero. Um, because if that piece equals zero, I don't care what the other pieces that zero times anything is zero or anything. Times zero is zero. So that's how we get when we add five over X. Could be negative. Positive? Five. Or when we subtract four over X. Could be negative for those here to answers. Yeah.

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